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x^2+6000000x-2*10^16=0
We add all the numbers together, and all the variables
x^2+6000000x-20000000000000000=0
a = 1; b = 6000000; c = -20000000000000000;
Δ = b2-4ac
Δ = 60000002-4·1·(-20000000000000000)
Δ = 80036000000000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{80036000000000000}=\sqrt{4000000000000*20009}=\sqrt{4000000000000}*\sqrt{20009}=2000000\sqrt{20009}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6000000)-2000000\sqrt{20009}}{2*1}=\frac{-6000000-2000000\sqrt{20009}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6000000)+2000000\sqrt{20009}}{2*1}=\frac{-6000000+2000000\sqrt{20009}}{2} $
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